Question

A solid cylinder of mass 0.1 kg having radius 0.2m rolls down an inclined plane of height 0.6m without slipping. The linear velocity the cylinder at the bottom of the inclined plane is
A. `28 ms^(-1)`
B. `2.8 ms^(-1)`
C. `280 ms^(-1)`
D. `0.28 ms^(-1)`

Answer 1

Correct Answer - B
According to the law of conservation of energy.
`(3)/(4)mv^(2)= mgh rArr v = sqrt((4gh)/(3)) = sqrt((4(9.8)(0.6))/(3))`
`= (28)/(10)= 2.8 ms^(-1)`.