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Black body at a temperature of `1640K` has the wavelength corresponding to maximum emission equal to `1.75mu m` Assuming the moon to be a perfectly black body the temperature of the moon if the wavelength corresponding to maximum emission is `14.35mum` is .
A. 100 K
B. 150 K
C. 200 K
D. 250 K

1 Answer

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Best answer
Correct Answer - C
`(T_(2))/(T_(1))=(lamda_(m_(1)))/(lamda_(m_(2)))=(1.75)/(14.35)`
`T_(2)=(1.75)/(14.35)xx1640=200K`

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