Calculation of molality of the solution.

Mass of ethylene glycol = 222.6 g

Molar mass of ethylene glycol = `2xx12+6xx1+2xx16=62h mol^(-1)`

`"Mass of solution (m)" = (" Mass of ethylene glycol / Molar mass")/(" Mass of solvent in kg")`

= `=((222.6g)//(62 g mol^(-1)))/(0.2 kg)=17.95 mol kg^(-1)=17.95 m`

Calculatrion of molarity of the solution.

Total mass of solution = Mass of solute + Mass of solvent

=222.6 + 200 422.6 g

Density of solution= 1.072 g `mol^(-1)`

`"Volume of solutin" = (" Mass of solution")/("Density of solution")=((422.6 g))/((1.072 g mol^(-1)))=394.2 mL`

=0.3942 L.

`"Molarity of solution (M)"=("Mass of ethylene glycon/Molar mass")/("Volume of solution in litres")`

`=((22.6g)//(62 g mol^(-1)))/((0.3942 L))=9.10 mol L^(-1)=9.10 M`