Question

Calculate the dispersive power for crown glass from the given data
`mu_(v)=1.523` and `mu_(r)=1.5145`.
A. 0.01639
B. 1.05639
C. 0.05639
D. 2.05639

Answer 1

Correct Answer - A
Here, `mu_(V) = 1.523` and `mu_(R) = 1.51875`
Mean refractive index,
`mu = (1.523 + 1.5145)/2 =1.51875`
Dispersive power is given by
`omega=(mu_(V)-mu_(R))/(mu-1) = (1.523 -1.5145)/(1.51875-1)= 0.01639`