Question

If acceleration of M is a then acceleration of m is

A. 3a
B. `(a)/(3)`
C. a
D. `sqrt(10)a`

Answer 1

Correct Answer - D
Net tensionon M
`=sqrt((3T)^(2)+T^(2))=sqrt(10)T`
Now from acceleration
x Tension=constant
`rArra_(M)(sqt(10)T)=a_(m)(T)rArra_(m)(T)rArra_(m)=(sqrt(10))a_(M)=sqrt(10)a`
OR
Net acceleration of m `=sqrt(a^(2)+(3a)^(2))=sqrt(10)a`