Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
24.5k views
in Solutions by (67.9k points)
recategorized by

Calculate the vapour pressure of a solution at 100°C containing 3g of cane sugar in 33g of water. (At wt. C = 12 , H = 1 , O = 16)

(A) 760 mm 

(B) 756.90 mm 

(C) 758.30 mm 

(D) None

1 Answer

+1 vote
by (79.4k points)
selected by
 
Best answer

Correct Option (B) 756.90 mm 

Explanation:

Vapour pressure of pure water (solvent) at 100°C, p0 = 760 mm.

Vapour pressure of solution, p = ?

Wt. of solvent , W = 33g

Wt. of solute , w = 3g

 Mol. wt. of water (H2O), M = 18

Mol. wt. of sugar (C12H22O11),

m = 12 x 12 + 22 x 1 + 11 x 16 = 342

According to Raoult’s law ,

= 760 – 3.19 = 756.90mm

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...