work done by the system
`=-nRTlog_(e)(P_(1))/(P_(2))=-2.303nRTlog((P_(1))/(P_(2)))`
`=-2.303xx5xx8.314xx300log((10)/(2))=-20.075xx10^(3)J`
Let M be the mass which can be lifted through a height of 1 m.
Work done in lifting the mass
`=Mgh=Mxx9.8xx1J`
So, `Mxx9.8=20.075xx10^(3)`
`M=2048.469kg`