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one mole of an ideal gas at 300k in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant presses of 3.0 atm. In this process. The change in entropy of surrroundings `(DeltaS)` in `J^(-1)` is
(1 L atm = 101.3 J)
A. 5.763
B. 1.013
C. `-1.013`
D. `-5.763`

1 Answer

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Best answer
Correct Answer - C
For work done by the system,
`q_(sys)=DeltaU+W`
`=0+PDeltaV`
`=3xx(2-1)=3L" atm"=3xx101.3J`
`DeltaS_(surr)=-(q_(sys))/(T)=-(303.9)/(300)`
`=-1.013JK^(-1)mol^(-1)`

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