Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
53 views
in Chemistry by (80.8k points)
closed by
The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be :
(Rydberg constant = `1.097 xx 10^(7) m^(-1)`)
A. `91 nm`
B. `192 nm`
C. `406`
D. `9.1xx10^(-6) nm`

1 Answer

0 votes
by (81.1k points)
selected by
 
Best answer
Correct Answer - 1
`1/lambda=R(1/n_(1)^(2)-1/n_(2)^(2)) 1/lambda=1.097xx10^(7) m^(-1)(1/1^(2)-1/oo^(2)) :. lambda=91xx10^(-9) m=91 m`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...