Question

A body starts revolving from rest in a circular path of radius 2 m with tangential acceleration a `=2tm//s^(2)`. If its total acceleration at t=2 sec. is `nsqrt(5) m//s^(2)`, then the value of n is:

Answer 1

`v=t^(2)`
t=2
`a=sqrt((a_(c))^(2)+(a_(t))^(2))`
`rArrsqrt(((v^(2))/(R))^(2)+a_(t^(2)))`
`rArrsqrt((8)^(2)+(4)^(2))rArr4sqrt(5)`