Question

A vessel of volume V = 7.5 1 contains a mixture of ideal gases at a temperature T = 300 K: v₁ = 0.10 mole of oxygen, v₂ = 0.20 mole of nitrogen, and v₃ = 0.30 mole of carbon dioxide. Assuming the gases to be ideal, find:

(a) the pressure of the mixture;

(b) the mean molar mass M of the given mixture which enters its equation of state pV = (m/M) RT, where m is the mass of the mixture.

Answer 1

(a) The mixture contains v₁ , v₂ and v₃ moles of O₂, N₂ CO₂ respectively. Then the total number of moles of the mixture

v = v₁+v₂+v₃

 we know, ideal gas equation for the mixture

(b) Mass of oxygen (O₂) present in the mixture : m₁ = v₁ M₁

Mass of nitrogen (N₂) present in the mixture : m₂ = v₂ M₂

Mass of carbon dioxide (CO₂) present in the mixture : m₃ = v₃ M₃

So, mass of the mixture