Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
564 views
in Mathematics by (94.1k points)
closed by
The line `y=mx+1` touches the curves `y=0x^(4)+2x^(2)+x` at two points `P(x_(1),y_(1))` and `Q(x_(2),y_(2))`. The value of `x_(1)^(2)+x_(2)^(2)+y_(1)^(2)+y_(2)^(2)` is
A. `4`
B. `6`
C. `8`
D. `10`

1 Answer

0 votes
by (91.2k points)
selected by
 
Best answer
Correct Answer - B
`(b)` The solution of `-x^(4)+2x^(2)+x=mx+1` is `x_(1)`, `x_(1)` and `x_(2)`, `x_(2)`.
`implies x^(4)-2x^(2)+(m-1)x+1=(x-x_(1))^(2)(x-x_(2))^(2)`
By comparing, we get
`x_(1)=1`, `x_(2)=-1`, `m=1impliesP(1,2)` and `Q(-1,0)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...