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Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median

Distance (in m) 0 - 1 1 - 2 2 - 3 3 - 4 4 - 5
Number of Students 40 80 62 38 30

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Distance (in m) 0 - 1 1 – 2 2 - 3 3 - 4 4 - 5
Number of Students 40 80 62 38 30
cf 40 120 182 220 250

\(\frac{n}{2}=\frac{250}{2}\) = 125

⇒ median class is 2 - 3, l = 2, h = 1, cf = 120, f = 62

median = \(l+\frac{\frac{n}{2}-cf}{f}\times i\)

= 2 + \(\frac{5}{62}\)

\(\frac{129}{62}=2\frac{5}{62}\)m or 2.08 m

50% of students jumped below \(2\frac{5}{62}\)m and 50% above it.

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