Question

Let ‘O’ be the centre of circle and AB and CD’ are chords. The distance of chord AB from ‘O’ is longer than the distance of chord CD from ‘O’ then one of the following is true. 

A) AB = CD 

B) AB > CD 

C) AB < CD 

D) AB + CD = 0

Answer 1

Correct option is (C) AB < CD

Chord which is nearer to the centre of the circle is larger than the chord which is situated far from the centre of the circle.

\(\because\) \(d_2>d_1\)

\(\therefore\) AB < CD

Answer 2

Correct option is  C) AB < CD