Correct option is (A) 1/6
Possible outcomes are S = {1, 2, 3, 4, 5, 6}
\(\therefore\) n(S) = 6
Number which is a perfect square and a perfect cube is 1. \((\because1^3=1\;\&\;1^2=1)\)
Hence, favourable outcome is n(E) = 1
\(\therefore\) Required probability is P(E) \(=\frac{n(E)}{n(S)}=\frac16.\)