Correct option is (C) ₹ 2166.66
Let the amount be P.
R = \(12\frac{1}{2}\%=\frac{25}{2}\%\)
T = 1 year
Amount after 1 year \(=P(1+\frac R{100})^1\)
\(\Rightarrow\) \(P(1+\frac R{100})\) = 2437.50 (Given)
\(\Rightarrow\) \(P(1+\frac{25}{200})\) = 2437.50
\(\Rightarrow\) \(P(1+\frac18)\) = 2437.50
\(\Rightarrow\) \(\frac{9P}8\) = 2437.50
\(\Rightarrow\) P = 2437.50 \(\times\frac89=\frac{19500}9\) = 2166.66
\(\therefore\) Amount is Rs 2166.66