First we can select 8 objects our of 20 for the first group in 20C8ways.
Now there are 12 objects left out of which we can select 7 objects for the second group in 12C7 ways.
Remaining 5 objects can be selected for the third group in 5C5 ways.
∴ Required number of ways = 20C8 × 12C7 × 5C5
