Correct Answer - Option 2 : 1
Concept:
Put \(f_x\)(1, 1) in \(f(x,y)=x^3 ysin\left ( \frac{\pi x}{2} \right )\)
Calculation:
Given:
\(f(x,y)=x^3 ysin\left ( \frac{\pi x}{2} \right )\)
putting \(f_x\)(1, 1) in above equation,
\(f(1,1)=1^3\times1 \times sin\left ( \frac{\pi \times 1}{2} \right )\)
\(f(1,1)= sin\left ( \frac{\pi}{2} \right )\)
\(f(1,1)= 1\)
∴ Option(2) is the correct answer.