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Consider the function \(y = x^2 + \dfrac{250}{x}\) At x = 5, the function attains.
1. Maximum
2. Minimum
3. 0
4. 1

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Correct Answer - Option 2 : Minimum

Concept:

A function attains a minimum value at a given point if the double derivative of that function at that point is positive.

A function attains a maximum value at a given point if the double derivative of that function at that point is negative.

Calculations:

Given function is \(y = x^2 + \dfrac{250}{x}\)

    Differentiating both sides w.r.t. x , we get ,

            \(dy \over dx \) = 2x - \(250 \over x^2\)

Putting \(dy \over dx \) = 0 , we get ,

2x - \(250 \over x^2\) = 0

Solving the above equation, we get, 

x = 5

Now, \(d^2y \over d^2x\) = 2 + \(500 \over x^3\)

Putting x = 5 in the above equation, we get ,

\(d^2y \over d^2x\) = 6, which is positive. 

So, the function attains a minimum value at x = 5

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