Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
234 views
in General by (103k points)
closed by
Two geometrically similar pumps are running at 1000 rpm speed (both). If one pump has impeller diameter of 0.3m and discharges 20 LPM against 20 m head, and the other pump gives half of this discharges rate; calculate head and diameter of second pump
1. 12.5 m and 0.12 m 
2. 10.5 m and 0.12 m
3. 10.5 m and 0.23 m 
4. 12.5 m and 0.23 m

1 Answer

0 votes
by (106k points)
selected by
 
Best answer
Correct Answer - Option 4 : 12.5 m and 0.23 m

Concept:

For a geometrically similar pump, similarity parameters are used to find the unknown quantities by making them equal for both the similar pumps.

The similarity parameters are 

Head rise coefficient - \(\frac{{H}}{{{N^2}{D^2}}}\)

Flow coefficient - \(\frac{Q}{{N{D^3}}}\)

Power coefficient - \(\frac{P}{{{N^3}{D^5}}}\)

For two similar pumps, the specific speed will also be the same.

Specific speed - \(\frac{{N\sqrt Q }}{{{H^{\frac{3}{4}}}}}\)

Calculation:

Given N1 = N2 = 1000 rpm, D1 = 0.3 m, H1 = 20 m, Q1 = 20 LPM;

Given the other pump gives half of this discharges rate ⇒ Q2 = 10 LPM;

From the specific speed relation,

\(⇒ \frac{{\sqrt {20} }}{{{{20}^{0.75}}}} = \frac{{\sqrt {10} }}{{H_2^{0.75}}}\)

⇒ H2 = 12.59 m;

From the flow coefficient relation,

\(⇒ \frac {20}{{0.3}^3} = \frac {10}{{D_2}^3}\)

⇒ D2 = 0.238 m;

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...