Correct Answer - Option 1 : 243 ≤ N ≤ 252
Calculation:
Let maximum marks of an examination be N.
Passing marks of an examination = 45N/100 = 9N/20
A's marks = 36
Pass marks of A reduced by = 100 - 68 = 32%
⇒ A's marks = 32/100 × 45/100 × N = 36
⇒ N = 250
∴ Total marks is in between = 243 ≤ N ≤ 252.