Correct Answer - Option 3 : 5
Concept:
(ABCD)
a = D* a
0 + C* a
1 + B* a
2 + A* a
3
Calculation:
Given: (43)x = (y3)8
⇒ 3 * x0 + 4 * x1 = 3 * 80 + y * 81
⇒ 3 + 4x = 3 + 8y
⇒ 4x = 8y
∴ x = 2y
Now, y < 8 and x > 4 (because the number represented in base x is 43 or redix is always greater )
The following are possible solutions
y = 3, 4, 5, 6, 7 (y < 8)
x = 6, 8, 10, 12, 14
Hence number of possible solution is five.