Correct Answer - Option 3 : 1/3
Given:
A finished work → 10 days
B finished work → 15 days
C finished work → 20 days
Calculations:
LCM of (10, 15, 20,) = 60
then the efficiency of A = 6, B = 4,and C = 3
A/Q
A B and C work alone
∴ A B and C work are done in 3 days → 6 + 4 + 3 = 13
Total work is 60 and A B and C are done 13 work in just 3 days
⇒ A B and C are done work 13 × 5 = 65 work in five cyclic in 3 × 5 = 15 days
Hence B work are work done 4 × 5 = 20 from total work of 60
∴ B work 20/60 = 1/3 part