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 A works twice as fast B. If both of them can together finish a piece of work in 12 days. Find B alone can do it in.
1. 24 days 
2. 27 days 
3. 36 days 
4. 48 days 
5. 68 days 

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Correct Answer - Option 3 : 36 days 

Given: 

A works twice as fast B

Together they finish the work in 12 days

Concept Used:

If a person takes t days to complete a work then in 1 day he will do 1/t part of the work

Calculation:

Let be A take X days to complete the work.

Then B takes 2X days to complete the work. 

A’s 1 day’s work 1\X

B ‘s1 day’s work 1\2X

A and B take 12 days to complete the work.

Net work done by (A + B) in 1 day 

⇒ 1/12 = 1/x + 1/2x

⇒ 1/12 = 3/2x

⇒ 2X = 36

⇒ X = 18

B can complete the work by himself in 36 days.

∴B will take 36 days.

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