Correct Answer - Option 2 : Bandwidth of System 2 is greater than bandwidth of System 1
Concept:
LTI system in time constant form is defined as:
\(C\left( s \right) = \frac{{K\left( {1 + s{\tau _1}} \right)\left( {1 + s{\tau _2}} \right) \cdots }}{{{s^n}\left( {1 + s{\tau _a}} \right)\left( {1 + s{\tau _b}} \right) \cdots }}\)
τ1, τ2 ⋯ and τa, τb ⋯ are time constants.
Bandwidth
For the first order systems bandwidth is defined as the reciprocal of the time constant.
\(BW = \frac {1}{\tau}\)
NOTE: Bandwidth in control systems represents the Speed of the system.
Calculation:
Given functions are
\(G\left( s \right) = \frac{1}{{3s + 1}}\) and \(G\left( s \right) = \frac{1}{{s + 1}}\)
Comparing with the standard forms we get time constants as:
τ1 = 3 sec and τ2 = 1 sec
BW1 = 1/3 Hz
BW2 = 1/1 Hz
BW2 > BW1
Hence statement 2 is correct.