Correct Answer - Option 4 : 78.4 L
2 mm
Concept:
Correction due to curvature:
\({{\rm{C}}_{\rm{c}}} = \frac{{{{\rm{d}}^2}}}{{2{\rm{R}}}}\)
d = Horizontal distance between two points in kM
R = Radius of curvature of earth in km = 6370 km
After submitting values of d and R in km we will get Cc in m
Correction due to curvature will be always negative
∴ Cc = - 0.0785 d2, d is substituted in km
Corrections due to refraction
\({{\rm{C}}_{\rm{R}}}{\rm{ = }}\frac{{\rm{1}}}{{\rm{7}}}{{\rm{C}}_{\rm{c}}}\)
\({{\rm{C}}_{\rm{R}}} = \frac{1}{7}\frac{{{{\rm{d}}^2}}}{{2{\rm{R}}}}\)
Correction for refraction is always positive
∴CR = 0.01122 d2, d is substituted in km
Combined correction:
C = Cc + CR
C = - 0.0785 d2 + 0.01122 d2
C = - 0.06735 d2
Explanation:
d = L km
Correction for curvature,
Cc = - 0.0785 d2
Cc = - 0.0785 L2 km
Cc = 78.5 L2 mm
Hence the correction for curvature of earth is 78.5 L2 in mm