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A small project consists of 3 activates P, Q and R to be executed in that sequence. The relationship between Time Duration (in ‘Units’ of time – T) and corresponding total direct cost (C units) for each of the activities, for alternate mutually exclusive possible durations for each activity, are tabulated herewith:

P

 

Q

 

R

 

T

C

T

C

T

C

8

250

6

340

8

400

9

235

7

320

10

375

10

225

8

295

12

350

11

215

9

275

 

 

 

For a total duration of 25 units of time, the least total direct cost for the complete project will be 
1. 965 units 
2. 950 units 
3. 940 units 
4. 925 units

1 Answer

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Best answer
Correct Answer - Option 4 : 925 units

Explanation:

The above problem is aptitude-based.To solve this, first we need to find out the various combinations of durations of P, Q, and R so that their sum becomes 25.

Case 1: If P = 8, then Q = 7 and R = 10 ⇒ their sum = 25 units of time

Total cost = 250 + 320 + 375 = 945 units

Case 2: If P = 9, then Q = 6 and R = 10 ⇒ their sum = 25 units of time

Total cost = 235 + 340 + 375 = 950 units

Case 3: If P = 9, then Q = 8 and R = 8 ⇒ their sum = 25 units of time

Total cost = 235 + 295 + 400 = 930 units

Case 4: If P = 10, then Q = 7 and R = 8 ⇒ their sum = 25 units of time

Total cost = 225 + 320 + 400 = 945 units

Case 5: If P = 11, then Q = 6 and R = 8 ⇒ their sum = 25 units of time

Total cost = 215 + 340 + 400 = 955 units

∴ Minimum Direct cost of the project is 930 units (Case 3) which is closer to option ‘4’.

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