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If w = α + iβ, where β ≠ 0 and z ≠ 1, satisfies the condition that

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If w = α + iβ, where β ≠ 0 and z ≠ 1, satisfies the  condition that ((w - bar wz)/(1 - z)) is purely real, then the set of values of z is

(a) |z| = 1, z ≠ 2

(b) |z| = 1 and z ≠ 1

(c) z = bar z

(d) None of the above

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Best answer

The correct option is (b) |z| = 1 and z ≠ 1

Explanation:

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