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If 1 m = 3.29 ft, how much distance is covered by Anil in 9 h 46 min 40 s, if he is running at the speed of 9 km/h?
1. 36 mile
2. \(\frac{28952}{528}\) mile
3. 37 mile
4. \(37\frac{4}{9}\) mile

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Correct Answer - Option 2 : \(\frac{28952}{528}\) mile

∵ 1 km = 1000 m

∴ 1000 m = 3.29 × 1000 ft and

\(9\text{ }\!\!~\!\!\text{ h }\!\!~\!\!\text{ }46\min 40\text{ }\!\!~\!\!\text{ s}=\frac{88}{9}\text{h}\)

\(\therefore Required~distance=9\times \frac{88}{9}km\) 

\(=9\times \frac{88}{9}\times 3290~ft\) 

\(=9\times \frac{88}{9}\times 3290~ft\) 

\(=9\times \frac{88}{9}\times 3290\times \frac{1}{3\times 1760}\text{mile}\) 

\(\frac{28952}{528}\) mile

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