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In the median of the following frequency distribution is 46, find the missing frequencies :

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Let the frequency of the class 30 - 40 be f1 and that of the class 50 - 60 be f2. The total frequency is 229

12 + 30 + f1 + 65 + f2 + 25 + 18 = 229

=> f1 + f2 = 79

It is given that median is 46., clearly, 46 lies in the class 40 - 50. So, 40 - 50 is the median class

So, l = 40, h = 10, f = 65 and C = 42 + f1, N = 229

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