Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
65 views
in General by (115k points)
closed by
The acceleration of Simple Harmonic Motion of a pendulum is proportional to
1. Length of pendulum
2. Time period
3. Angular velocity
4. Displacement

1 Answer

0 votes
by (152k points)
selected by
 
Best answer
Correct Answer - Option 4 : Displacement

For simple harmonic motion, the equations are as given

x = A sinωt

ẋ = Aωcosωt

\(\begin{array}{l} \ddot x = - {\rm{A}}{{\rm{\omega }}^2}{\rm{sin\omega t}}\\ \ddot x = - {{\rm{\omega }}^2}{\rm{x}} \end{array}\)

⇒ Acceleration ∝ displacement.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...