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Periodic time of simple pendulum is given by
1. \(2\pi \sqrt {\frac{l}{g}}\)
2. \(2\pi \sqrt {\frac{g}{l}} \)
3. \(\frac{1}{{2\pi }}\sqrt {\frac{g}{l}} \)
4. \(\frac{1}{{2\pi }}\sqrt {\frac{l}{g}}\)

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Correct Answer - Option 1 : \(2\pi \sqrt {\frac{l}{g}}\)

A simple pendulum is one which can be considered to be a point mass suspended form a string or rod of negligible mass.

The period \(T = 2\pi \sqrt {\frac{l}{g}}\)

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