Question

A pure inductive coil allows a current of 10 A to flow from a 230 V, 50 Hz supply. Find inductance of the coil
1. 0.05 H
2. 0.07 H
3. 0.09 H
4. 0.7 H

Answer 1

Correct Answer - Option 2 : 0.07 H

Here E_V = 230 V; I_V = 10 A; f = 50 Hz

Inductive reactance, \({X_L} = \frac{{{E_V}}}{{{I_V}}} = \frac{{230}}{{10}} = 23{\rm{\Omega }}\)

Now X_L = 2 π f L

∴ Inductance of the coil, \(L = \frac{{{X_L}}}{{2\pi f}} = \frac{{23}}{{2\pi \times 50}} = 0.073H\)