Question

The input voltage to a converter is \({V_i} = 100\sqrt 2 \sin \left( {100\pi t} \right)V\) .The current drawn by the converter is The current drawn by the converter is

 

\({i_1} = 10\sqrt 2 \sin \left( {100\pi t - \frac{\pi }{3}} \right) + 5\sqrt 2 \sin \left( {300\pi t+ \frac{\pi }{4}} \right) + 2\sqrt 2 \sin \left( {500\pi t - \pi /6} \right)A.\)The active power drawn by the converter is

1. 181 W
2. 500 W
3. 707 W
4. 887 W

Answer 1

Correct Answer - Option 2 : 500 W

Active power draws = Power drawing by fundamental

Is1 = RMS value of fundamental current, V_s = RMS value of source voltage

\(\begin{array}{l} = {V_s}{I_{s1}}\cos {\phi _1}\\ = 100 \times 10 \times \cos 60 \end{array}\)

= 500 W