Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Aptitude by (108k points)
closed by
If a2 + b2 = 25, x2 + y2 = 17 and ax + by = 8, then what is the value of (ay - bx)?
1. 25
2. 33
3. 19
4. 21

1 Answer

0 votes
by (111k points)
selected by
 
Best answer
Correct Answer - Option 3 : 19

Given:

a2 + b2 = 25, x2 + y2 = 17, ax + by = 8 

Formulas used:

(a + b)2 = a2 + b2 + 2ab

(a - b)2 = a2 + b2 - 2ab

(ax + by)2 + (ay - bx)= (a2 + b2) × ( x2 + y2)

Calculation:

By using the above formula; 

(ax + by)2 + (ay - bx)= (a2 + b2) × ( x2 + y2)

⇒ 8+ (ay - bx)2 = 25 × 17

⇒  (ay - bx)2 = 425 - 64 = 361

⇒ (ay - bx) = √361 = 19 

∴  (ay - bx) = 19 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...