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in Three-dimensional geometry by (33.2k points)

Two lines L1: (x – x1)/a1 = (y – y1)/b1 = (z – z1)/c1

and L2: (x – x2)/a2 = (y – y2)/b2 = (z – z2)/c2 are coplanar if

|((x2 - x1,y2 - y1,z2 - z1),(a1,b1,c1),(a2,b2,c2))| = 0

If the lines (x – 1)/2 = (y + 1)/3 = (z – 1)/4 and (x – 3)/1 = (y – k)/2 = z/1 are coplanar, the value of k is

(a) 3/2

(b) 9/2

(c) –2/9 

(d) –3/2

1 Answer

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by (36.6k points)
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Best answer

Answer is (b) 9/2

Since both the lines are coplanar, so

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