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If the function of \(f(x)=\dfrac{x}{x-1}\) express f(3x) in terms of f(x)
1. \(\dfrac{3f(x)}{2f(x)+1}\)
2. \(\dfrac{3f(x)}{3f(x)-1}\)
3. \(3f(x) - 1\)
4. \(\dfrac{3f(x)}{3f(x)-3}\)

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Best answer
Correct Answer - Option 1 : \(\dfrac{3f(x)}{2f(x)+1}\)

Concept:

According to the rule of a linear function, we know that, if, \(f(x)=x\), 

 \(\Rightarrow f(ax)=ax\) 

where a is the coefficient of x.

Calculation:

\(f(x)=\dfrac{x}{x-1}\)      ---(1)

 \(\Rightarrow(x-1)f(x)=x\)

 \(\Rightarrow xf(x)-f(x)=x\)

 \(\Rightarrow xf(x)-x=f(x)\)

 \(\Rightarrow x(f(x)-1)=f(x)\)

 \(\Rightarrow x=\dfrac{f(x)}{f(x)-1}\)      ---(2)

Replacing x with 3x in equation(1), we get

\(f(3x)=\dfrac{3x}{3x-1}\)

Now, substituting the value of x from equation(2) in this equation, we get

\(f(3x)=\dfrac{\dfrac{3f(x)}{f(x)-1}}{\dfrac{3f(x)}{f(x)-1}-1}\)

 \(\Rightarrow f(3x)=\dfrac{\dfrac{3f(x)}{f(x)-1}}{\dfrac{3f(x)-f(x)+1}{f(x)-1}}\)

 \(\Rightarrow f(3x)=\dfrac{3f(x)}{2f(x)+1}\)

Hence\(f(3x)=\dfrac{3f(x)}{2f(x)+1}\)

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