Correct Answer - Option 1 : There exist at least two natural numbers which are prime to each other
Concept:
The Pigeonhole Principle: Let there be n boxes and (n + 1) objects. Then, under any assignment of objects to the boxes, there will always be a box with more than one object in it. This can be reworded as, if m pigeons occupy n pigeonholes, where m > n, then there is at least one pigeonhole with two or more pigeons in it.
Calculation:
We divide the set into n classes {1, 2}, {3, 4},......{2n - 1, 2n}.
By the pigeonhole principle, given n +1 elements at least two of them will be in the same case {2k - 1, 2k} (1 ≤ k ≤ n). But 2k - 1 and 2k are relatively prime because their difference is 1.