Correct Answer - Option 2 :
\(\dfrac{10}{3}\ g\)
Given:
Gold in the alloy is 80%
Calculation:
The quantity of gold in 50g of alloy
50 × 80/100 = 40g
The quantity of gold changed to 75%
75% = 40g
⇒ 100% = (40/75) × 100 = 160/3
Quantity added
\(\frac{160}{3} \ - \ 50\)
⇒ \(\frac{160 \ - \ 150}{3} \) = \(\frac{10}{3} \)g
∴ The \(\frac{10}{3} \)g will be added.