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 ST and NT denote the standard time and the normal time, respectively, to complete a job. Allowance = LL × ST, where 0 < LL < 1. Which one of the following relationships is correct?
1. ST = \(\frac{NT }{(1-LL)}\)
2. ST = NT (1 + LL)
3. ST = \(\frac{NT}{(1+LL)}\)
4. ST = NT (1 - LL)

1 Answer

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Best answer
Correct Answer - Option 1 : ST = \(\frac{NT }{(1-LL)}\)

Explanation:

Time study:

  • The classical approach to time study was developed by W. Taylor in 1911, and it is an accepted procedure for production analysis.
  • It is an analysis of a worker’s performance against a time standard.
  • Time studies are normally performed on short repetitive production types of tasks.
     

Standard Time:

It is the time needed to complete an operation by an employee working at 100 % efficiency with unavoidable delays.

It is given by:

Standard Time = Normal Time + Allowance Time

Standard Time = \(\frac{{Normal\;time}}{{1\; - \;allowance\;fraction}}\)

i.e. ST = \(\frac{NT }{(1-LL)}\)

∴ option (1) is the correct answer.

Cycle Time:

It is the total time required for a worker to complete one cycle of operation.

Machine Cycle time:

It is the total time for a machine to finish one complete cycle. It includes loading and unloading.

Normal Time:

The normal time for a particular employee is rated against the average job element-time. It is given by:

\(Normal\;Time = \frac{{Average\;element\;\times\;Performance\;rating}}{{100}}\)

Allowance Time:

  • It includes personal factors as well as unavoidable constraints encountered in the work situation.
  • It includes all unavoidable delays but rules out all avoidable delays.

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