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If W is load on a circular slab of radius R, the maximum radial moment at the centre of the slab is-
1. \(\frac{{W{R^2}}}{{16}}\)
2. \(\frac{{3W{R^2}}}{{32}}\)
3. \(\frac{{W{R^2}}}{{32}}\)
4. \(\frac{{3W{R^2}}}{{16}}\)

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Correct Answer - Option 4 : \(\frac{{3W{R^2}}}{{16}}\)

Radial moment at the centre of the Circular slab is

\({M_R} = \frac{W}{{16}} \times \left( {\left( {3 + \mu } \right)\left( {{R^2} - {r^2}} \right)} \right)\)

Where MR = Radial moment

R = radius of slab

μ = Poisson’s ratio

r = any section at a distance r from centre of the slab

W = load on circular slab

For maximum radial moment at centre

r = 0 and μ = 0

therefore, \({M_R}\; = \frac{W}{{16}} \times 3 \times {R^2} = \frac{{3W{R^2}}}{{16}}\)

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