Correct Answer - Option 2 : Rs. 40
Given:
Total sum S7 = Rs. 700
Each prize is Rs. 20 less than its preceding prize
Formula used:
Sn = (n/2)[2a + (n - 1)d]
Where, Sn = sum of first n terms, a = first term, d = common difference, n = number of terms
Calculation:
Let the value of 1st prize be x
According to the question,
Value of 2nd prize = x - 20
Value of 3rd prize = x - 40
Similarly, we can write the values of seven prizes are
x, x - 20, x - 40, x - 60, x - 80, x - 100, x - 120
Now, it can be observed that the values of these prizes in an A.P.
Here, a = x, d = -20 and n = 7
S7 = (n/2)[2a + (n - 1)d]
700 = (7/2)[2 × x + (7 - 1) × (-20)]
⇒ 200 = [2x + 6 × (-20)]
⇒ 200 = 2x - 120
⇒ 320 = 2x
⇒ x = 160
Least value of the price = x - 120
⇒ 160 - 120
⇒ Rs. 40
∴ The least value of the prize is Rs. 40.