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In a simultaneous throw of a pair of dice, find the probability of getting a total of 9 or more.
1. 5/18
2. 5/12
3. 2/7
4. 2/36

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Correct Answer - Option 1 : 5/18

Calculation:

When 2 dice are throw total outcome = 36

Number of outcomes where sum of throws is 9 = (4, 5), (5, 4), (3, 6) and (6, 3) = 4

Number of outcomes where sum of throws is 10 = (4, 6), (6, 4), and (5, 5) = 3

Number of outcomes where sum of throws is 11 = (6, 5), and (5, 6) = 2

Number of outcomes where sum of throws is 12 = (6, 6) = 1

Total number of ways of getting sum 9 and above = 4 + 3 + 2 + 1 = 10 ways

Probability of getting  sum 9 and above = 10/36 = 5/18

∴ Required probability is 5/18.

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