LIVE Course for free

Rated by 1 million+ students
Get app now
JEE MAIN 2023
JEE MAIN 2023 TEST SERIES
NEET 2023 TEST SERIES
NEET 2023
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
29 views
in Physics by (30.0k points)
closed by
Two point charges 5μC and 4μC are 10 cm apart. Find the force by which they will repel each other.
1. 10 N
2. 36 N
3. 18 N
4. 9 N

1 Answer

0 votes
by (55.2k points)
selected by
 
Best answer
Correct Answer - Option 3 : 18 N

CONCEPT:

  • Coulomb’s law is an inverse square law of force that describes the electrostatic force between charged particles.
  • Electrostatic Force: between two charges q1 and q2 at the distance of R is given by:

\(F=\frac{1}{4\pi ϵ_0}\frac{q_1q_2}{R^2} \)

where F is the electrostatic force, q1 and qare the charges, and ϵ0 is the electrical permittivity of the vacuum.

CALCULATION:

Given that q1 = 5μC and q2 = 4μC R = 10cm = 0.1m;

We know \(F=\frac{1}{4\pi ϵ_0}\frac{q_1q_2}{R^2} \)

\(F=9×10^9×\frac{5μC \times 4μC}{0.1^2} \)

\(F=9×10^9×\frac{5​​​​ \times 10^{-6} \times 4 \times 10^{-6}}{0.1^2} =18\)

F = 18 N

So the correct answer is option 3.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...