Correct Answer - Option 2 : -1
Concept used:
If m and n are positive rational numbers, then
loga(mn) = n.logam
loga(b) = (log b)/(log a)
Calculation:
loga(b) = (log b)/(log a)
⇒ log100(0.01) = (log 0.01)/(log 100)
⇒ (log 10-2)/(log 102)
⇒ {-2(log 10)}/{2(log 10)} ----{loga(mn) = n.logam}
⇒ -1
∴ The value of log100(0.01) is - 1.
If m and n are positive rational numbers, then
loga(mn) = n.logam
log1010 = 1