Correct Answer - Option 2 : 0
Given:
Length of Shatabdi Express = 180 meters
Time taken by Shatabdi Express to cross a tree = 12 seconds
Length of August Express = 240 meters
Time taken by August Express to cross the same tree = 12 seconds
Formula Used:
Speed = Distance/Time
Calculation:
Normal speed of Shatabdi Express (S) = 180/12 = 15 m/s
Similarly, Normal speed of August Express (A) = 240/20 = 20 m/s
Hence we obtain:
4S – 3A = (4 × 15) – (3 × 20) = 0
∴ The required value of (4S – 3A) is 0