Correct Answer - Option 3 : sin 10πt + sin 13t
Concept:
Consider a signal x(t) = Am sin (ωt)
The time period of the signal T = 2π / ω seconds
Consider a signal with the combination of two signals y(t) = sin ω1t + sin ω2t
The time period of the signal 1 T1 = 2π / ω1 seconds
The time period of the signal 2 T2 = 2π / ω2 seconds
When both signals are added, take the ratio of T1 and T2, it must be rational in order to result as a periodic signal.
Calculation:
- Signal sin 10πt is periodic with a time period of 0.2 s
- Signal sin 31t is periodic with time period 2π / 31 s
- Signal sin (10πt + 31) is periodic with time period 0.2 s
Condition to find time period for a mixed-signal is the ratio of the two time periods must be rational.
For signal sin 10πt + sin 13t
sin 10πt is periodic with a time period(T1) of 0.2 s
sin 13t is periodic with a time period(T2) of 2π / 13 s
T1 / T2 = 13 / 10π ⇒ Irrational
So the signal sin 10πt + sin 13t is a non-periodic signal.