Correct Answer - Option 2 : 300 m
Given:
Speed of slower train = 100 km/h
Speed of faster train = 46 km/h
The faster train passes the man in slower train in 20 sec.
Formula used:
Relative speed = S1 – S2
Speed = Distance/Time
Solution:
Relative Speed = (100 – 46) km/h
⇒ Relative Speed = 54 km/h
⇒ {(54 × 1000)/(1 × 3600)} m
⇒ 15 m/s
Distance covered in 20 sec = 15 m/s × 20 s = 300 m
∴ The length of faster train is 300 m.