Correct Answer - Option 2 : 0.97

**Concept:**

**Dryness fraction of steam(x): **

Ratio of mass of dry steam to the summation of the mass of dry steam and mass of water vapour in the mixture.

\( x = \frac{{{m_g}}}{{{m_g}~ +~ {m_f}}}\)

where m_{g} = mass of dry steam, m_{f} = mass of water vapour

__Calculation:__

__Given:__

mg = 50 kg, mf = 1.5 kg

\(x = \frac{{50}}{{50 ~+ ~1.5}}\)= 0.97