Correct Answer - Option 2 : 0.97
Concept:
Dryness fraction of steam(x):
Ratio of mass of dry steam to the summation of the mass of dry steam and mass of water vapour in the mixture.
\( x = \frac{{{m_g}}}{{{m_g}~ +~ {m_f}}}\)
where mg = mass of dry steam, mf = mass of water vapour
Calculation:
Given:
mg = 50 kg, mf = 1.5 kg
\(x = \frac{{50}}{{50 ~+ ~1.5}}\)= 0.97
