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in Arithmetic Progression by (238k points)
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The sum of the 5th term and the 15th term of an AP is 116. The sum of the third term and the 7th term of the same AP is 56. Find the common difference of the AP.
1. 7
2. 6
3. 5
4. 8

1 Answer

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Best answer
Correct Answer - Option 2 : 6

Given:

The sum of the 5th term and the 15th term of an AP is 116. The sum of the third term and the 7th term of the same AP is 56.

Formula used:

nth term of an AP, Tn = a + (n - 1)d, where ‘a’ is the first term, ‘n’ is the total number of terms and ‘d’ is the common difference.

Calculation:

Let the first term is ‘a’ and common difference is‘d’.

From the question

T5 + T15 = 116

⇒ (a + 4d) + (a + 14d) = 116

⇒ 2a + 18d = 116

⇒ a + 9d = 58     ----(1)

Similarly,

T3 + T7 = 156

⇒ (a + 2d) + (a + 6d) = 56

⇒ 2a + 8d = 56

⇒ a + 4d = 28     ----(2)

By subtracting equation (2) from (1)

5d = 30

⇒ d = 6

∴ Common difference is 6.

by (10 points)
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